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Hasan buys two kinds of cloth materials for school uniforms,shirt material that costs him Rs50 per metre and trouser material that costs him Rs90 per metre. For every 2 metres of the trouser material he buys 3 metres of the shirt material. He sells the materials at 12%and 10% profit respectively. His total sale is Rs36,660.How much trouser material did he buy? |
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Answer» -step EXPLANATION:EQUATIONS with linear expressions in one variable only are known as linear equations in one variable. An algebraic EQUATION is an equality involving variables. It has an equality sign(=). The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).==========================================================Solution:Let Hasan bought 2x m of trouser material and 3x m of the shirt material. Per metre selling price(S.P) of the trouser material = ₹90+90×12/100= 90 + 1.2× 9= 90 + 10.8=₹100.80 Per metre selling price(S.P) of trouser of shirt material= ₹50+ 50× 10/100= ₹ 50 + 5=₹55 Given: TOTAL AMOUNT of sale= ₹ 36660100.80 x (2x) + 55 x (3x) = ₹36660 201.60 x + 165x = 36660 366.60 x = 36660 X= 36660/366.60x = 100Trouser material = 2x m = (2×100)m = 200m.Hasan bought 200 m of trouser material.=========================================================Hope this will help you |
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