1.

HBr and HI can reduce H_(2)SO_(4).HCl can reduce KMnO_(4) and HF can reduce

Answer»

`H_(2)SO_(4)`
`KMnO_(4)`
`K_(2)Cr_(2)O_(7)`
NONE of the above

Solution :`F^(-)` can be oxidised to `F_(2)` only be ELECTROLYSIS.


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