HCF of two numbers is 5 and their LCM is 60 if one number is 50 find o

1.	HCF of two numbers is 5 and their LCM is 60 if one number is 50 find other number
Answer» Answer: GIVEN : HCF = 5, LCM = 60 and One NUMBER is 15. FIND : We have to find the other number. SOLUTION : • Let other number be M. We know that.. \star{ \bold{ \BOXED{Product\:of\:TWO\:numbers\: = \: LCM\:\times\:HCF}}}⋆ Productoftwonumbers=LCM×HCF Product of two zeros = One number × Other number. So, One number × Other number = LCM × HCF _______ (eq 1) Put the known values in (eq 1) => 15 × M = 60 × 5 => 15M = 300 => M = 20 _____________________________ \huge{\bold{M\:=\:20}}M=20 (Other number) ___________ [ ANSWER ] _____________________________ ☆ VERIFICATION : From above calculations we have M = 20 Put value of M in (eq 1) => 15 × 20 = 60 × 5 => 300 = 300 L.H.S. = R.H.S.

HCF of two numbers is 5 and their LCM is 60 if one number is 50 find other number

Answer»

Answer:

GIVEN :

HCF = 5, LCM = 60 and One NUMBER is 15.

We have to find the other number.

SOLUTION :

• Let other number be M.

We know that..

\star{ \bold{ \BOXED{Product\:of\:TWO\:numbers\: = \: LCM\:\times\:HCF}}}⋆

Productoftwonumbers=LCM×HCF

Product of two zeros = One number × Other number.

So,

One number × Other number = LCM × HCF _______ (eq 1)

Put the known values in (eq 1)

=> 15 × M = 60 × 5

=> 15M = 300

=> M = 20

_____________________________

\huge{\bold{M\:=\:20}}M=20

(Other number)

___________ [ ANSWER ]

_____________________________

☆ VERIFICATION :

From above calculations we have M = 20

Put value of M in (eq 1)

=> 15 × 20 = 60 × 5

=> 300 = 300

L.H.S. = R.H.S.