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| 1. |
HCF of two numbers is 5 and their LCM is 60 if one number is 50 find other number |
| Answer» <html><body><p><strong>Answer:</strong></p><p>GIVEN :</p><p></p><p>HCF = 5, LCM = 60 and One <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> is 15.</p><p></p><p><a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> :</p><p></p><p>We have to find the other number.</p><p></p><p>SOLUTION :</p><p></p><p>• Let other number be M.</p><p></p><p>We know that..</p><p></p><p>\star{ \bold{ \<a href="https://interviewquestions.tuteehub.com/tag/boxed-7665690" style="font-weight:bold;" target="_blank" title="Click to know more about BOXED">BOXED</a>{Product\:of\:<a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a>\:numbers\: = \: LCM\:\times\:HCF}}}⋆ </p><p>Productoftwonumbers=LCM×HCF</p><p> </p><p> </p><p></p><p>Product of two zeros = One number × Other number.</p><p></p><p>So,</p><p></p><p>One number × Other number = LCM × HCF _______ (eq 1)</p><p></p><p>Put the known values in (eq 1)</p><p></p><p>=> 15 × M = 60 × 5</p><p></p><p>=> 15M = <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a></p><p></p><p>=> M = 20</p><p></p><p>_____________________________</p><p></p><p>\huge{\bold{M\:=\:20}}M=20</p><p></p><p>(Other number)</p><p></p><p>___________ [ ANSWER ]</p><p></p><p>_____________________________</p><p></p><p>☆ VERIFICATION :</p><p></p><p>From above calculations we have M = 20</p><p></p><p>Put value of M in (eq 1)</p><p></p><p>=> 15 × 20 = 60 × 5</p><p></p><p>=> 300 = 300</p><p></p><p>L.H.S. = R.H.S.</p></body></html> | |