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Heat evolved in the reaction `H_(2)+Cl_(2) rarr 2HCl` is 182 kJ Bond energies H- H = 430 kJ/mole, `Cl-Cl = 242kJ//"mole"`. The H-Cl bond energy isA. `245 "KJ mol"^(-1)`B. `427 "KJ mol"^(-1)`C. `336 "KJ mol"^(-1)`D. `154 "KJ mol"^(-1)` |
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Answer» Correct Answer - B `H_(2)+Cl_(2)rarr 2HCl , Delta H = -182 kJ` `Delta H=Sigma(B.E.)_(R )-Sigma (B.E.)_(P)-182 =(430+242)-2xx(B.E.)_(H-Cl)` `therefore (B.E.)_(H-Cl)=427 KJ mol^(-1)` |
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