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Heat liberated when 100 mL of 1N NaOH is neutralised by 300 ml of 1N HCl |
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Answer» A) 11.46 kJ 100 ml of N NaOH will CONTAIN `=0.4gm" "NaOH-=(1)/(10)`mole Now, `underset("0.1 mole")(OH^(-))+underset("0.1 mole")(H^(+)) to underset("0.1 mole")(H_(2)O)` `because` When 1 mole of `H_(2)O` is formed, the heat produced =57.3 kJ `therefore` When 0.1 mole `H_(2)O` is formed, the heat produced `=57.3xx0.1=5.73kJ` |
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