1.

Heat liberated when 100 ml of in NaOH is neutralized by 300 ml of in HCl ……(a) 22.92 Ici (b) 17.19 kJ (c) 11.46 kJ (d) 5.73 Id

Answer»

Base = V1 = 100ml 

N1 = 1N 

Acid = V2 = 300ml

N2 = 1N 

Enthalpy of neutralization of 1000 ml = 57.3 kJ. 

∴ Enthalpy of neutralization of 100 ml x 100 = 5.73KJ / 1000 x 100 = 5.73 kJ.



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