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Heat liberated when 100 ml of in NaOH is neutralized by 300 ml of in HCl ……(a) 22.92 Ici (b) 17.19 kJ (c) 11.46 kJ (d) 5.73 Id |
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Answer» Base = V1 = 100ml N1 = 1N Acid = V2 = 300ml N2 = 1N Enthalpy of neutralization of 1000 ml = 57.3 kJ. ∴ Enthalpy of neutralization of 100 ml x 100 = 5.73KJ / 1000 x 100 = 5.73 kJ. |
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