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Heat of 20 K cal is supplied to the system and8400 J of external work is done on the systemso that its volume decreases at constantpressure. The change in internal energy is(J = 4200 J /kcal) |
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Answer» According to 1st law of thermodynamicsdU = q + W 8.4 kJ = (20 × 4.2 kJ) + WW = 8.4 kJ - 84 kJW = -75.6 kJW = -75.6/4.2 = -18 kcal Work done by system is 18 kcal |
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