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Heat of combustion of ethanol at constant pressure and at temperature TK is found to be `-q J" mol"^(-1)`. Hence, heat of combustion (in J `mol^(-1)`) of ethanol at the same temperature and at constant volume will be :A. RT - qB. `-(q+RT)`C. q - RTD. q + RT |
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Answer» Correct Answer - A `C_(2)H_(5)OH(l)+3O_(2)(g)rarr2CO_(2)(g)+3H_(2)O(l)` `Deltan_(g)=2-3=-1` `DeltaH=DeltaU+Deltan_(g)RT` `DeltaU=DeltaH+RT=RT-q` |
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