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heat of formation of ` H_(2)O is -188 kJ // mol and H_(2)O_(2) is -286 kJ // mol` . The enthaply change for the reaction ` 2H_(2)O_(2) to 2H_(2)O+O_(2)` isA. 196 kJB. `-196 kJ`C. 984 kJD. `-984 kj` |
Answer» Correct Answer - a `H_(2)+1/2 O_(2)to H_(2)O,DeltaH=-188kJ mol^(-1)` `H_(2) + O_(2) to H_(2)O_(2) , DeltaH =286 kJ mol ^(-1)` multiply Eqs.(i) and (ii) by 2 `2H_(2)+O_(2) to 2H_(2)O, DeltaH=-376 kJ mol^(-1)` `2H_(2)+2O_(2) to 2H_(2)O_(2) , DeltaH =- 572 kJ mol^(-1)` Eq .(iii) - Eq.(iv) `2H_(2)O_(2) to 2H_(2)O + O_(2), DeltaH_(r) =+196 kJ` |
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