1.

Heat of neutralisation of `NaOH` and `HCl` is `-57.46 kJ //` equivalent. The heat of ionisation of water in `kJ //mol` is `:`A. `-57.46`B. `+57.46`C. `-114.92`D. `+114.92`

Answer» Correct Answer - B
`H^(+)+OH^(-)rarr H_(2)O, DeltaH=-57.46kJ //eq.`
`(` heat of neutralisation `)`
`H_(2)O rarr H^(+)+OH^(-), DeltaH=57.46kJ//eq. or kJ //mol`


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