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Helium gas goes through a cycle ABCDA (consisting of two isochoric and isobaric lines) as shown in figure Efficiency of this cycle is nearly: (Assume the gas to be close to ideal gas) A. `15.4%`B. `9.1%`C. `10.5%`D. `12.5%` |
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Answer» Correct Answer - A Helium is monoatomic gas, for which `C_(v)3/2R` and `C_(p)= 5/2R` Work done by the gas in one complete cycle `W= area ABCDA=P_(0)V_(0)` (figure) From A to B, heat given to gas `= nC_(v)DeltaT` `=1xx(5/2R) DeltaT= 5/2 (2P_(0)) Delta V= 5P_(0)V_(0)` From C to D and from D to A, heat is rejected by the gas, `Efficiency= ("work done by the gas"//"cycle")/("total heat given to gas"//"cycle")` `=(P_(0)V_(0))/(3/2P_(0)V_(0)+5P_(0)V_(0))=2/(13)xx100= 15.4%` |
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