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Hello koi hai kyaaaaaaaaa ji( ꈍᴗꈍ) |
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Answer» a). Connecting them all in series would GIVE us the HIGHEST resistance. {R}_{eff}\:=\:{R}_{1}\:+\:{R}_{2}\:+\:{R}_{3}R eff
=R 1
+R 2
+R 3
{R}_{eff}R eff
= 22Ω b). Connecting these two resistances in parallel would give us LOWEST resistance. 1/R = 1/6 + 1/12 1/R = 2+1/12 1/R = 3/12 R = 4Ω Explanation: ʜɴᴊɪ..ʜᴍ ʜ ɴᴀ |
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