1.

Henderson's equation is pH = pK_(a) + log.(["salt"])/(["acid"]). If the acid gets half neutralized the value of pH will be : [pK_(a) = 4.30]

Answer»

4.3
2.15
8.6
7

Solution :`PH = pK_(a) + log.(["SALT"])/(["ACID"])`
`pH = 4.3 + log .((1)/(2))/((1)/(2)) = 4.3 + log 1, pH = 4.3 + 0 = 4.3`.


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