1.

Henry'slawconstan for thesolubilityof methane in benzene is 4.27 xx 10^(-5) mm^(-1) Hgmol dm^(-3) at constant temperature.Calculate thesolubilityof methane at760 mm Hg pressureat sametemperature .

Answer»


Solution :GIVEN :HENRY'slawconstant = k
`=4.27 xx 10^(-5) MM^(-1) Hg"mol" dm^(-3)`
Pressure ofthe gas = P = 760 mm Hg
`K= 4.27xx 10^(-5) mm^(-1) "mol" dm^(-3)`
`=3245 xx 10^(-5) xx 760 atm^(-1) "mol" dm^(-3)`
`=3.245 xx 10^(-2)atm^(-1)"mol" dm^(-3)`
`P= 760 mm = (760)/(760)atm= 1 atm`
By Henry's,law
`S= K xx P = 3.245 xx 10^(-2) atm^(-1) "mol" dm^(-3) xx 1 atm `
`=3.245 xx 10^(-2)"mol" dm^(-1)`


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