1.

Heptane and octane form an ideal solution. At 373 K, the vapour pressure of the two liquid components are 105.2 kPa and 46.8 kPa respectively, what will be the vapour pressure of a mixture of 26.0 g of heptane and 35 g of octane ?

Answer»

7.308 kPa
73.08 kPa
730.8 kPa
7308 kPa

Solution :`P=x_(A)P_(A)^(@)+x_(B)P_(B)^(@) "" P_("HEPTANE")^(@)=105.2kPa`
`P_("octane")^(@)=46.8kPa`
`P_("Total")=P_("Heptane")^(@)X_("Heptane")+P_("Octane")^(@)X_("Octane")`
`=105.2xx(((26)/(100))/((26)/(100)+(35)/(114)))+46.8xx(((35)/(114))/((26)/(100)+(35)/(114)))`
`=73.08` kPa


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