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Here The Sum Of The Series Is 4+8+12+16+….. =612. Find How Many Terms Are There In The Series? |
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Answer» This is an A.P. in which a=4, d=4 and Sn=612 Then, n/2[2a+(N1)d]=612 => n/2[2*4+(n1)*4]=612 => 4n/2(n+1)=612 => n(n+1)=306 => n^2+n306=0 => n^2+18n17n306=0 => n(n+18)17(n+18)=0 => (n+18)(n17)=0 => n=17. Number of terms=17. This is an A.P. in which a=4, d=4 and Sn=612 Then, n/2[2a+(n1)d]=612 => n/2[2*4+(n1)*4]=612 => 4n/2(n+1)=612 => n(n+1)=306 => n^2+n306=0 => n^2+18n17n306=0 => n(n+18)17(n+18)=0 => (n+18)(n17)=0 => n=17. Number of terms=17. |
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