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Hey Armies !!please solve this |
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Answer» Answer: LET the GIVEN polynomials be f(x) and g(x). When f(x) and g(x) are DIVIDED by (x-2) they leave the same remainder. I.e (x-2) is a factor of f(x) and g(x). It means 2 is the zero of f(x) and g(x) So that, f(2) = g(2) 2x³+ax²+3x-5 = x³+x²-4x+a 2(2)³+a(2)²+3(2)-5 = 2³+2²-4(2)+a 2(8)+a(4)+6-5 = 8+4-8+a 16+4a+1 = 4+a 17+4a = 4+a 4a-a = 4-17 3a = -13 a = -13/3. |
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