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                                    `HgCl_(2)` and `I_(2)` both when dissolved in water containing `I^(-)` ions the pair of species formed is:A. `HgI_(2)mI_(3)^(-)`B. `HgI_(2),I^(-)`C. `Hgl_(4)^(2-), I_(3)^(-)`D. `Hg_(2)I_(2),I^(-)` | 
                            
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Answer» Correct Answer - C `HgCl_(2)` and `I_(2)` both when dissolved in water containing `I^(-)` ions, the pair of species formed is `HgI_(4)^(2-)` and `I_(3)^(-)`. In aqueous solution, `I_(2)` reacts with `I^(-)` and maintains the following equilibrium `I_(2)+I^(-) ltimplies I_(3)^(-)` `Hg^(2+)` gives ppt. of `HgI_(2)` on reaction with `I^(-)`. But `HgI_(2) +2I^(-) to underset("Red ppt")(HgI_(2))darr+2Cl^(-)` `HgI_(2) + 2I^(-) ltimplies [HgI_(4)]^(2-)` `HgI_(2) + 2I^(-) ltimplies [HgI_(4)]^(2) + 2I^(-) ltimplies [HgI_(4)]^(2-)`  | 
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