InterviewSolution
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InterviewSolution
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Which of the following lanthanoid ions is diamagnetic? (Atomic number of `Ce=58,Sm=62,Eu=63,Yb=70`]A. `Ce^(2+)`B. `Sm^(2+)`C. `Eu^(2+)`D. `Yb^(2+)` |
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Answer» Correct Answer - D Lanthanoid ion with no unpiared electronis diamagnetic in nature. `Ce_(58) =[Xe]4f^(2)5d^(0)6s^(2)` `Ce^(2+) =[Xe]4f^(2)` (two unpaired electrons) `Sm_(62) = [Xe]4f^(6)5d^(0)6s^(2)` `Sm^(2+) = [Xe]4f^(6)` (six unpaired electrons) `Eu_(63) =[Xe]4f^(6)5d^(0)6s^(2)` `Eu^(2+) =[Xe]4f^(7)` (seven unpiared electrons) `Yb_(70)=[Xe]4f^(14)5d^(0)6s^(2)` `Yb^(2+) = [Xe]4f^(14)` (no unpaired electrons) Because of the absence of unpaired electrons, `Yb^(2+)` is diamagnetic. |
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