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                                    The oxidation state of `Cr` in `K_(2)Cr_(2)O_(7)` is:A. `+5`B. `+3`C. `+6`D. `+7` | 
                            
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Answer» Correct Answer - C Let the oxidation state of Cr is x `K_(2)Cr_(2)O_(7)` `therefore 2(+1)+2x=7(-2)=0` `2+2x-14=0` `2x-12=0` `2x=12` `x=12/2 = +6`  | 
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