1.

HgO do not require reducing agent while isolation because

Answer»

HIGH + ve `DELTA G^(@)`
low `-ve DeltaG^(@)`
high-ve `DeltaG^(@)`
low `+ve DeltaG^(@)`

Solution :Due to low `-ve DeltaG^(@)` , HgO can be DECOMPOSED to Hg SIMPLY by heating


Discussion

No Comment Found