1.

HI can not be prepared by which of the following methods ?

Answer»

`Pl_(3) + H_(2)O to `
`Kl + H_(2)SO_(4)("conc") to`
`H_(2) + I_(2) to`
`I_(2) + H_(2)s to`

Solution :KI will be oxidised to `I_2` in PRESENCE of cone. `H_2SO_4` .


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