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Hi guys please help me in solving Q23 and Q24 |
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Answer» 23) 3424) (1) RS 518124) (2) 1/16. {see attachment}Step-by-step explanation:Ans 23:s= a+b+c/2 51 +37+20/2 =54area = √s(s-a)(s-b)(s-c) = √54 (54-51)(54-37)(54-20) =√54(3)(17)(34) {simplest form} = √(3*2*3*3)*(3)*(17)*(17*2) = 3*2*3*17 = 306m²area NEEDED for flower beds = 306/9 = 34∴ 34 flower beds are required to occupy the spaceAns 24 (1):Radius of the base = r = 0.5 m = 0.5 × 100 cm = 50 cmHeight= h = 1.4 m = 1.4 × 100 cm = 140 cmSurface area to be tin-coated = 2( 2πrh + πr²)= 2[(2 × 3.14 × 50 × 140) + (3.14 × 50 x 50)]COST of tin-coating at the rate of Rs. 50 per 1000 cm2 = Rs 1000Total cost = 50/1000 × 103620= Rs 5181Hope it clears your query.Please mark me brainliest. |
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