High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact validates if A=1?(a) High-boost filtering reduces to regular Highpass filtering(b) High-boost filtering reduces to regular Lowpass filtering(c) All of the mentioned(d) None of the mentionedI got this question during an interview.This intriguing question originated from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

High boost filtered image is expressed as: fhb = A f(x, y) – flp(x,

1.	High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact validates if A=1?(a) High-boost filtering reduces to regular Highpass filtering(b) High-boost filtering reduces to regular Lowpass filtering(c) All of the mentioned(d) None of the mentionedI got this question during an interview.This intriguing question originated from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right CHOICE is (a) HIGH-boost filtering reduces to regular Highpass filtering The EXPLANATION: High boost filtered IMAGE is MODIFIED as: fhb = (A-1) f(x, y) +f(x, y) – flp(x, y) i.e.fhb = (A-1) f(x, y) + fhp(x, y). So, when A=1, High-boost filtering reduces to regular Highpass filtering.

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