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Hlo freinds plz don't spam Give me correct solution. ​

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Answer:

Consider a Line EF...i.e.

E-----------------------F...

Between AB And CD ......

nD is ll To aB And CD.....

So X = + .....(SUPPOSE these VALUES).

[APX = 180° -150° = 30°

So....... = 30°........([Z...Lies on EF)

ND [CYP = 180° - 120° = 60°

i.e. = 60°.......([Z ..lies On EF).....

So x = + =60° + 30° = 90°....



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