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Hlo freinds plz don't spam Give me correct solution. |
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Answer» Answer: Consider a Line EF...i.e. E-----------------------F... Between AB And CD ...... nD is ll To aB And CD..... So X = a° + B°.....(SUPPOSE these VALUES). [APX = 180° -150° = 30° So.......a° = 30°........([Z...Lies on EF) ND [CYP = 180° - 120° = 60° i.e. B° = 60°.......([Z ..lies On EF)..... So x = a° + B° =60° + 30° = 90°....✓✓✓ |
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