1.

How are (1) butanone (2) Pentan-3-one obtained using (i) alcohol and (ii) geminal dihalide?

Answer»

Solution :(1) Using alcohol:
(1) Butan-2-ol on CONTROLLED oxidation with `K_(2)Cr_(2)O_(7)` and dillute `H_(2)SO_(4)` forms butanone.
`CH_(3)-UNDERSET("Butan-2-ol") overset(OH)overset(|)(CH)-CH_(2)-CH_(3)+[O]underset("dil". H_(2)SO_(4))overset(K_(2)Cr_(2)O_(7))(to CH_(3)- underset("Butanone")overset(O)overset(||)(CO-CH_(2)-CH_(3)+H_(2)O`
(2) Pentan-3-ol on oxidation with `K_(2)Cr_(2)O_(7)` and dilute `H_(2)SO_(4)` forms Pentan-3-one.
(2) Using geminal dihalide:
(1) When 2, 2-Dichlorobutane is hydrolysed by boiling with aqueous KOH, Butanone is OBTAINED.

`CH_(3) - CH_(2)- underset("Butanone")overset(O)overset(||)(C)-CH_(3)+H_(2)O`
(2) When 3,3-dichloropentane is hydrolysed by boiling with aqeous `KOH`, Pentan-3-one is obtained.

`implies CH_(3)-CH_(2)-underset("Pentan-3-one")overset(O) overset(||)(C-CH_(2))-CH_(3)+H_(2)O`


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