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How are xenon fluorides XeF_2 , XeF_4 and XeF_6 obtained ?

Answer»

SOLUTION :These xenon fluorides are OBTAINED by direct reaction between `Xe and F_2` , under different CONDITIONS as shown below :
`underset("(Excess)")(Xe(g)) + F_2(g) overset(673K, 1 " BAR " )to XeF_2(s)`
` underset("(1 : 5ratio )" ) ( Xe(g) + 2F_2 (g)) ovreset(873 K , 7 " bar ")to Xe F_4 (s)`
`underset("(1 : 20 ratio )")(Xe(g) + 3F_2(g)) overset(573 K, 60 - 70 " bar ") to XeF_6 (s)`


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