1.

How are XeO_3 and XeOF_4 prepared ?

Answer»

Solution :Hydrolysis of `XeF_4 and XeF_6` with WATER produces `XeO_3` .
`6XeF_4 + 12H_2O to 4Xe + 2XeO_3 + 24HF + 3O_2 `
`XeF_6 + 3H_2O to XeO_3 + 6HF`
PARTIAL hydrolysis of `XeF_6` GIVES `XeOF_4`.
`XeF_6 + H_2O to XeOF_4 + 2HF` .


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