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How are XeO_3 and XeOF_4 prepared ? |
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Answer» Solution :Hydrolysis of `XeF_4 and XeF_6` with WATER produces `XeO_3` . `6XeF_4 + 12H_2O to 4Xe + 2XeO_3 + 24HF + 3O_2 ` `XeF_6 + 3H_2O to XeO_3 + 6HF` PARTIAL hydrolysis of `XeF_6` GIVES `XeOF_4`. `XeF_6 + H_2O to XeOF_4 + 2HF` . |
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