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How are `XeO_3` and `XeOF_4` prepared? |
Answer» (i) `XeO_(3)` can be prepared in two ways as shown. `6XeF_(4) + 12 H_(2) O to 4 Xe + 2 XeO_(3) + 24 HF + 3O_(2)` `X eF_(6) + 3H_(2)O to XeO_(3) + 6 HF` (ii) `XeOF_(4)` can be prepared using `XeF_(6)`. `XeF_(6) +H_(2)O to XeOF_(4) + 2HF` |
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