1.

How are `XeO_3` and `XeOF_4` prepared?

Answer» (i) `XeO_(3)` can be prepared in two ways as shown.
`6XeF_(4) + 12 H_(2) O to 4 Xe + 2 XeO_(3) + 24 HF + 3O_(2)`
`X eF_(6) + 3H_(2)O to XeO_(3) + 6 HF`
(ii) `XeOF_(4)` can be prepared using `XeF_(6)`.
`XeF_(6) +H_(2)O to XeOF_(4) + 2HF`


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