how can three resistors of 1, 2 and 3 ohms be arranged in a circuit in

1.	how can three resistors of 1, 2 and 3 ohms be arranged in a circuit in order to get a combined resistance of 11/4 ohm?
Answer» Answer: ANSWER (a) Equivalent RESISTANCE is R eq =R 1 +R 2 +R 3 =(1+2+3)Ω=6Ω (B) Current in the circuit is given by I= R E I= 6 12 =2Ω Potential drop across 1Ω, V 1 =IR 1 =2×1=2V Potential drop across 2Ω,V 2 =IR 2 =2×2=4V Potential drop across 3Ω,V 3 =IR 3 =2×3=6V

how can three resistors of 1, 2 and 3 ohms be arranged in a circuit in order to get a combined resistance of 11/4 ohm?

Answer»

Answer:

ANSWER

(a)

Equivalent RESISTANCE is

=(1+2+3)Ω=6Ω

(B)

Current in the circuit is given by I=

=2Ω

Potential drop across 1Ω, V

=IR

=2×1=2V

Potential drop across 2Ω,V

=IR

=2×2=4V

Potential drop across 3Ω,V

=IR

=2×3=6V

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how can three resistors of 1, 2 and 3 ohms be arranged in a circuit in order to get a combined resistance of 11/4 ohm? ​

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how can three resistors of 1, 2 and 3 ohms be arranged in a circuit in order to get a combined resistance of 11/4 ohm?