1.

How can three resistors of resistances 2Ω, 3 Ω, and 6Ω be connected to give a total resistance of (i) 4 Ω, (ii) 1 Ω ?​

Answer»

Answer:

To obtain a TOTAL RESISTANCE of 4 Ω from three resistors of given resistances, Firstly, CONNECT the TWO resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance. Hence, the total resistance of the circuit is 4 Ω. ... ⇒ 1/R = 1 Ω.

Explanation:

hope it was HELP full



Discussion

No Comment Found

Related InterviewSolutions