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How Do Convert Or Display The Date Or Time As String?

Answer»

Simply use CAST to appropriate CHAR or VARCHAR DATA type (big enough). Example:

CREATE TABLE t1 (t time, d date. ts timestamp);
INSERT INTO t1 (t,d,ts) VALUES (‘14:59:23’, ‘2007-12-3 1’, ‘2007-12-31 14:59’);
SELECT CAST(t as varchar(13)), CAST(d as varchar( 10)), CAST(ts as varchar(24)) FROM t1;

Firebird would output TIMES in HH:MM:SS.mmmm format (HOURS, minutes, seconds, milliseconds), and dates in YYYY-MM-DD (year, month, day) format.

if you wish a different formatting you can either use SUBSTRING to extract the info from char column, or use EXTRACT to buld a different string:

SELECT extract(day from d)||’.’||extract(month from d)||’.‘||extract(year from d) FROMt1;

Simply use CAST to appropriate CHAR or VARCHAR data type (big enough). Example:

CREATE TABLE t1 (t time, d date. ts timestamp);
INSERT INTO t1 (t,d,ts) VALUES (‘14:59:23’, ‘2007-12-3 1’, ‘2007-12-31 14:59’);
SELECT CAST(t as varchar(13)), CAST(d as varchar( 10)), CAST(ts as varchar(24)) FROM t1;

Firebird would output times in HH:MM:SS.mmmm format (hours, minutes, seconds, milliseconds), and dates in YYYY-MM-DD (year, month, day) format.

if you wish a different formatting you can either use SUBSTRING to extract the info from char column, or use EXTRACT to buld a different string:

SELECT extract(day from d)||’.’||extract(month from d)||’.‘||extract(year from d) FROMt1;



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