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How do we differentiate between CO_(3)^(2-) and SO_(3)^(2-) in dilute H_(2)OSO_(4) group ? ( Note : These are sodium salts ? |
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Answer» By passing gas liberated with DILUTE `H_(2)SO_(4)` through LIME water. `CaCO_(3)+CO_(2)+H_(2)OrarrCa(HCO_(3))_(2)("soluble")` `SO_(3)^(2-)+2H^(+)rarrSO_(2)+H_(2)O,Ca(OH)_(2)+SO_(2)rarr CaSO_(3)darr("white")+H_(2)O` `CaSO_(3)+H_(2)O+SO_(2)rarrCa(HSO_(3))_(2)("soluble")`. `(2)CO_(3)^(2-)+2H^(+)rarrCO_(2)+H_(2)O,Cr_(2)O_(7)^(2-)+H^(+)+CO_(2)rarr"No reaction"` `SO_(3)^(2-)+2H^(+)rarrSO_(2)+H_(2)O,Cr_(2)O_(7)^(2-)+2H^(+)+3SO_(2)rarr2Cr^(3+)("green solution")+3SO_(4)^(2-)+H_(2)O` `(3)Pb^(2+)+OS_(3)^(2-)rarrPbSO_(3)darr("white"),2Pb^(2+)+2CO_(3)^(2-)+H_(2)Orarrubrace(Pb(OH)_(2)darr+PbCO_(3)darr)_("while")+CO_(2)` `(4) 2Ag^(+)+CO_(3)^(2-)rarrAg_(2)CO_(3)darr("white")"",""2Ag^(+)+SO_(3)^(2-)rarrAg_(2)SO_(3)darr("white")` |
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