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| 1. |
How do you explain the presence of an aldehydic group in a glucose molecule ? |
| Answer» Solution :Glucose reacts with hydroxylamine `(NH_2OH)` to form a monoxime and adds one molecuole of hydrogen cyanide (HCN) to give a CYANOHYDRIN. Therefore, glucose contains a carbonyl group which can be EITHER an aldehyde or a ketone. On mild oxidation with `Br_(2)-H_(2)O`, glucose GIVES a carboxylic acid , i.e, gluconic acid containing the same carbon atoms as present in glucose. This INDICATES that the carbonyl group presnet in glucose is an aldehydic group and not a ketonic group. For structure of oxime , cyanohydrin and gluconic acid. | |