How does current in a pure capacitor vary in terms of phase angle with

1.	How does current in a pure capacitor vary in terms of phase angle with the voltage across it?
Answer» Solution : If`V = V_(0) SIN omega t` `q = CV = CV_(0) sin omega t` `I = (DQ)/(d t) = omega CV_(0) cos omega t` or `I = omega CV_(0) sin (omega t + (pi)/(2))` So, the current leads the APPLIED VOLTAGE in phase by `pi//2`.

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How does current in a pure capacitor vary in terms of phase angle with the voltage across it?

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