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How does the total energy stored in the capacitors in the circuit shown in the figure change when first switch K_(1) is closed (process-1) and then switch K_(2) is also closed (process-2) Assume that all capacitor were initially uncharged? |
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Answer» Increases in process-1  equivalent CAPACITANCE `=(5C)/3` When `k_(2)` is closed no increasing in ENERGY when `k_(1)` is closed `E=1/2cqV^(2)=1/2(5C)/3V^(2)=(5CV^(2))/6` |
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