how far from the base of the building a ladder of length 2.9 metre sho

1.	how far from the base of the building a ladder of length 2.9 metre should be placed so that it exactly reaches at the height 2 metre of the building
Answer» Step-by-step explanation: The ladder FORMS a right angled TRIANGLE with the wall and the base with length of the ladder being the length of hypotenuse of this triangle. Hypotenuse =25 m Base =7 m Height =25 2 −7 2 =24 m Now the ladder SLIDES. In the new POSITION, the hypotenuse of the new right angled triangle will be the same. The top slides down by a distance 4m. HENCE, the height is 24−4=20 m. Let the base slide by a distance x. Therefore, hypotenuse =25 m Base =(7+x) m Height =20 m By Pythagoras Theorem, we get 25 2 −20 2 =(7+x) 2 ∴(7+x)=15 Hence, x=8

how far from the base of the building a ladder of length 2.9 metre should be placed so that it exactly reaches at the height 2 metre of the building

Answer»

Step-by-step explanation:

The ladder FORMS a right angled TRIANGLE with the wall and the base with length of the ladder being the length of hypotenuse of this triangle.

Hypotenuse =25 m

Base =7 m

Height =25

−7

=24 m

Now the ladder SLIDES. In the new POSITION, the hypotenuse of the new right angled triangle will be the same.

The top slides down by a distance 4m. HENCE, the height is 24−4=20 m. Let the base slide by a distance x. Therefore, hypotenuse =25 m

Base =(7+x) m

Height =20 m

By Pythagoras Theorem, we get

−20

=(7+x)

∴(7+x)=15

Hence, x=8