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How high a column of air would be necessary to cause the barometer to read 76 cmHg, if the atmosphere were of uniform density 1.2 kg//m^(3) ? The density of Hg = 13.6 xx 10^(3) kg//m^(3). |
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Answer» Solution :Let the height of the air column be h metres and acceleration due to GRAVITY, G `"metre s"^(-2)`. `therefore` PRESSURE corresponding to `76 cm(0.76 m)` of `Hg = 0.76 xx (13.6 xx 10^(3)) xx g` and pressure corresponding to .h. metres of air `= h xx 1.2 xx g`. THUS, `h xx 1.2 xx g = 0.76 xx 13.6 xx 10^(3) xx g` or h = 8613 metres. |
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