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How high must a body be lifted so that it gain P.E. equal to its KE while moving with a velocity of `30m//s`?Take `g=10m//s^(2)` |
Answer» Here, `h=?v=30m//s, g=10m//s^(2)` If m is mass of the body, then as `P.E. =K.E. :. mgh=(1)/(2)mv^(2), h=(v^(2))/(2g)=(30xx30)/(2xx10)=45m` |
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