How is a²-b² equivalent to (a+b)(a-b)help

1.	How is a²-b² equivalent to (a+b)(a-b)help
Answer» Step-by-step explanation: a² - b² = (a+b)(a-b) Here a and b are the REAL numbers. (a+b)(a-b) =a(a-b)+b(a-b) [Addition Distributive Law] =a²-ab+ba-b² [Addition Distributive Law] =a²-ab+ab-b² [MULTIPLICATION Commutative Law] =a²+0-b² [Addition Law of Identity] =a²-b² [Addition Law of Identity] so, a² - b² = (a+b)(a-b) Addition Distributive Law: (A + B) X = (A X) + (B X) Multiplication Commutative Law: XY=YX Addition Law of Identity: A+(-A)=0 and A+0=A

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Step-by-step explanation:

a² - b² = (a+b)(a-b)

Here a and b are the REAL numbers.

(a+b)(a-b)

=a(a-b)+b(a-b) [Addition Distributive Law]

=a²-ab+ba-b² [Addition Distributive Law]

=a²-ab+ab-b² [MULTIPLICATION Commutative Law]

=a²+0-b² [Addition Law of Identity]

=a²-b² [Addition Law of Identity]

so, a² - b² = (a+b)(a-b)

Addition Distributive Law: (A + B) X = (A X) + (B X)

Multiplication Commutative Law: XY=YX

Addition Law of Identity: A+(-A)=0 and A+0=A

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