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How is divisibility of 7 rule different fromdivisibility of 11 rule Show with an example |
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Answer» Answer: Divisor Divisibility CONDITION Examples 7 Subtracting 2 times the last digit from the rest gives a MULTIPLE of 7. (Works because 21 is DIVISIBLE by 7.) 483: 48 − (3 × 2) = 42 = 7 × 6. Subtracting 9 times the last digit from the rest gives a multiple of 7. 483: 48 − (3 × 9) = 21 = 7 × 3. |
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