1.

How is methylamine prepared by Hoffmann bromamide degradation reaction ? Give equation.

Answer»

Solution :When acetanoide is treated with `Br_(2)` and AQ. NaOH gives
METHYL amine
`UNDERSET("Acetamide")(CH_(3)-overset(O)overset(|)C-NH_(2))+Br_(2)+4NaOH_((aq))overset(Delta)rarr underset("methylamine")(CH_(3)NH_(2)+2NaBr)+Na_(2)CO_(3)+2H_(2)O`


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