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How is methylamine prepared by Hoffmann bromamide degradation reaction ? Give equation. |
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Answer» Solution :When acetanoide is treated with `Br_(2)` and AQ. NaOH gives METHYL amine `UNDERSET("Acetamide")(CH_(3)-overset(O)overset(|)C-NH_(2))+Br_(2)+4NaOH_((aq))overset(Delta)rarr underset("methylamine")(CH_(3)NH_(2)+2NaBr)+Na_(2)CO_(3)+2H_(2)O` |
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