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How is propan - 2 - ol prepared by hydration of an alkene? |
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Answer» SOLUTION :PROPENE with cold `80%` `H_(2)SO_(4)` gives isopropyl hydrogensulphate which further on boiling with water gives (isopropyl ALCOHOL) Propan - 2- ol. `UNDERSET("propene")(CH_(3))-CH=CH_(2)+underset("cold 80% conc.")(HOSO_(3)H)rarrunderset("isopropyl hydrogen sulphate")(CH_(3)-underset(""OSO_(3)H)underset("|")"CH"-CH_(3))` `CH_(3)-underset(""OSO_(3)H)underset("|")"CH"-CH_(3)+H_(2)overset("boil")rarrunderset("Propan - 2- ol.")underset("isopropyl alcohol")(CH_(3)-underset(OH)underset("|")"CH"-CH_(3))` |
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