1.

How is propanoic acid is prepared starting from (a) an alcohol (b) an alkylhalide (c) an alkene

Answer»

SOLUTION :Preparation of propanoic ACID from,
(a) Alcohol:
`underset("(propan-1-ol)")(CH_3-CH_2-CH_2-OH) OVERSET(H^(+)//K_2Cr_2O_7)(to) underset("(propanoicacid)")(CH_3-CH_2-COOH)`
(b) Alkylhalide :
`underset("(ethyl bromide)")(CH_3-CH_2-Br) overset("Mg/ether")(to) underset("(ethyl magnesium bromide)")(CH_3-CH_2-MGBR) underset((ii)H^(+) // H_2O)overset((i) CO_2)(to) underset("(propanoic acid)")(CH_3CH_2COOH ) + MgBr(OH) `
(c ) Alkene :
`underset("ETHENE ")(CH_2 =CH_2) overset(HCl)(to) underset("ethyl chloride")(CH_3-CH_2-Cl) underset(-NaCl)overset(NaCN)(to) underset("ethylcyanide")(CH_3-CH_2-CN) underset("excess")overset(H^(+)//H_2O)(to) underset("propanoicacid")(CH_3CH_2COOH)`


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