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How is the energy of activation determined ? |
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Answer» Solution :For the given reaction, rate constants `k_(1) a nd k_(2)` are measured at two DIFFERENT temperatures `T_(1)` and `T_(2)` respectively. Then `log_(10).(k_(2))/(k_(1))=E_(a)(T_(2)-T_(1))/(2.303RxxT_(1)xxT_(2))` where `E_(a)` is the energy of activation. Hence by SUBSTITUTING appropriate values, energy of activation `E_(a)` for the reaction is determined. |
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