1.

How long 3 ampere current should be pass to obtain 0.1 mol Cl_(2) gas through electrolysis of molten NaCl ?

Answer»

220 MINUTE
330 minute
55 minute
110 minute

Solution :`2CL^(-) to Cl_(2)+2e^(-)`
`W=(epsixxixxt)/(96500)`
`0.1xx71=(35.5)/(96500)xx3xxt`(second).
t=6433.33 second=107.22 minute`~~`110 minute


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