Saved Bookmarks
| 1. |
How long a current of 3 amp has to be passed through a solution of AgNO_(3) to coat a metal surface of 80 cm^(2) with 0.005 mm thick layer ? Density of Ag is 10.5 g//cm^(3). |
|
Answer» Solution :No. of eq. of Ag deposited `= ("wt. of Ag deposited in grams")/("equivalent wt. of Ag")` `= ("volume " xx " density")/("equivalent weight")` `= ("surface area " xx " thickness " xx " density")/("equivalent weight")` `= (80 xx 0.0005 xx 10.5)/(108)` `= (7)/(1800) = 0.0039` Mole of ELECTRIC charge = 0.0039 FARADAY `= 0.0039 xx 96500` coulombs 376.35 coulombs. `THEREFORE` duration of electrolysis `= ("charge in coulombs")/("current in amp")` `= (376.35)/(3)s` `~~ 125s`. |
|