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How many""^(235)U is consumed in a day in an atomic power house operating at 400 MW , provided the whole of mass ""^(235)Uis converted into energy? |
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Answer» Solution :Power = 400 MW = `400 xx10^(6)W,` TIME = 1 day = 86 , 400 s. Energy produced , E = power `xx ` time `=400xx10^(6)xx86,400=3.456xx10^(13)J` As the whole of mass is converted into energy , by Einstein.s mass - energy relation `E =Mc^2` `M = E/(c^2) = (3.456xx10^(13))/((3xx10^(8))^2) =3.84xx10^(-4)kg = 0.384 g`. |
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