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How many 3-digit numbers are possible using permutations with repetition allowed if digits are 1-9?(a) 504(b) 729(c) 1000(d) 720The question was asked in quiz.This intriguing question originated from Permutations-2 in portion Permutations and Combinations of Mathematics – Class 11

Answer»

The correct CHOICE is (b) 729

To explain I WOULD SAY: 1-9 digits which means 9 digits are possible. We have to arrange 3 digits at a time out of 9 digits with repetition allowed. So, total PERMUTATIONS are n^r = 9^3 = 729.



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