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How many 3 - digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?1. 52. 103. 154. 20 |
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Answer» Correct Answer - Option 4 : 20 Given: Digits =2, 3, 5, 6, 7 and 9 Concept used: Divisibility rule of 5: The number is divided by 5, if theunit digit of a number is either 5 or 0. Calculation: Unit digit can only be 5. There is only 1 possible way to fillunitplace. Remaining placescan be filled by 2, 3, 6, 7 or9. There is 5possible ways to fill ten'splace. There is 4 possible ways to fill hundredth place as digits cannot be repeated. Total numbers that can be formed = 1× 5× 4= 20 ∴ 3 - digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 is 20. |
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